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Adjacent Increasing Subarrays Detection II

Medium
25%
Updated 8/1/2025

Asked by 1 Company

Adjacent Increasing Subarrays Detection II

What is this problem about?

The Adjacent Increasing Subarrays Detection II coding problem is a more advanced version of the previous task. Instead of checking if a specific length kk works, you are asked to find the maximum possible value of k such that there exist two adjacent strictly increasing subarrays of length kk.

Why is this asked in interviews?

Google frequently asks this to see if candidates can move from "detection" to "optimization." It tests your ability to recognize that if a length kk is valid, any length smaller than kk is also valid. This monotonic property is a huge hint that a more efficient search strategy can be applied.

Algorithmic pattern used

This problem often involves the Binary Search on Answer interview pattern. Since the possible values for kk range from 11 to n/2n/2, you can binary search for the largest kk that satisfies the condition. Within each binary search step, you use a linear scan (the "Detection I" logic) as the validator. Alternatively, a more optimized O(N)O(N) approach can be achieved using a Two Pointers or dynamic programming-style array to store the maximum increasing length at each position.

Example explanation

Input: nums = [1, 2, 3, 4, 4, 5, 6, 7]

  1. The longest increasing sequence is [1, 2, 3, 4] (length 4) and the next is [4, 5, 6, 7] (length 4).
  2. Wait—the condition is "strictly increasing." The second 4 breaks the strict increase if we tried to combine them.
  3. However, we can have two adjacent subarrays: [1, 2, 3] and [4, 5, 6], both of length k=3k=3.
  4. The algorithm would identify k=3k=3 as the maximum.

Common mistakes candidates make

  • Linear Search for k: Incrementing kk from 1 upwards, which results in O(N2)O(N^2) complexity, potentially failing on large inputs.
  • Ignoring the Overlap: Not realizing that one long increasing sequence of length LL can provide two adjacent subarrays of length L/2L/2.
  • Strict vs. Non-Strict: Forgetting that a single "equal" value (like 5, 5) resets the increasing count.

Interview preparation tip

Whenever an interview question asks for the "maximum value of X" and the property is "if X works, X-1 also works," always consider Binary Search on the result.

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