The Adjacent Increasing Subarrays Detection II coding problem is a more advanced version of the previous task. Instead of checking if a specific length works, you are asked to find the maximum possible value of k such that there exist two adjacent strictly increasing subarrays of length .
Google frequently asks this to see if candidates can move from "detection" to "optimization." It tests your ability to recognize that if a length is valid, any length smaller than is also valid. This monotonic property is a huge hint that a more efficient search strategy can be applied.
This problem often involves the Binary Search on Answer interview pattern. Since the possible values for range from to , you can binary search for the largest that satisfies the condition. Within each binary search step, you use a linear scan (the "Detection I" logic) as the validator. Alternatively, a more optimized approach can be achieved using a Two Pointers or dynamic programming-style array to store the maximum increasing length at each position.
Input: nums = [1, 2, 3, 4, 4, 5, 6, 7]
[1, 2, 3, 4] (length 4) and the next is [4, 5, 6, 7] (length 4).4 breaks the strict increase if we tried to combine them.[1, 2, 3] and [4, 5, 6], both of length .5, 5) resets the increasing count.Whenever an interview question asks for the "maximum value of X" and the property is "if X works, X-1 also works," always consider Binary Search on the result.