The Bitwise OR of Adjacent Elements coding problem is a straightforward array manipulation exercise. Given an array of integers, you are tasked with creating a new array where each element at index i is the result of a bitwise OR operation between the elements at index i and i+1 of the original array. This problem is a great introduction to bitwise operators and simple array traversals.
Companies like Adobe use this as an introductory question for junior roles or internships. It tests your basic understanding of the | (OR) operator and your ability to handle array indexing correctly without going out of bounds. While simple, it ensures that a candidate can perform basic tasks efficiently before moving on to more complex algorithmic challenges.
This problem follows a simple Simulation or Linear Traversal pattern. You iterate through the array from the first element up to the second-to-last element, performing the OR operation on the current element and its neighbor. The time complexity is , and the space complexity is for the new array (or if the result is printed directly).
Suppose you have an array: [1, 2, 4, 8]
1 | 2 = 0001 | 0010 = 0011 (3)2 | 4 = 0010 | 0100 = 0110 (6)4 | 8 = 0100 | 1000 = 1100 (12)
The resulting array is [3, 6, 12].The most common mistake is an "off-by-one" error in the loop range, which leads to an IndexOutOfBounds exception when trying to access i+1 for the last element. Another mistake is confusing the bitwise OR (|) with the logical OR (||) or the bitwise XOR (^).
Always double-check your loop boundaries. When you're accessing i+1, your loop should generally run until length - 2. This is a small detail that shows attention to code safety.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Single Number | Easy | Solve | |
| Check if Bitwise OR Has Trailing Zeros | Easy | Solve | |
| Construct the Minimum Bitwise Array I | Easy | Solve | |
| Count Triplets with Even XOR Set Bits I | Easy | Solve | |
| Find the K-or of an Array | Easy | Solve |