The Compare Version Numbers interview question asks you to compare two version strings (like "1.01" and "1.001"). Versions are divided into "revisions" by dots. You should compare revisions from left to right. A revision's value is its integer interpretation, meaning leading zeros are ignored ("01" equals "1"). If one version has more revisions than the other, the missing revisions are treated as 0.
Apple and Amazon ask the Compare Version Numbers coding problem to test your string parsing and "clean code" skills. It’s a simulation problem that requires careful handling of edge cases, such as different lengths and large numbers of dots. It evaluates if you can handle input without over-complicating the logic with complex regex.
The most effective String interview pattern here is Splitting and Two Pointers.
. character into lists of strings.v1 > v2 return 1, if v1 < v2 return -1.v1: "1.0.1", v2: "1"
v1 = ["1", "0", "1"], v2 = ["1"].1 and 1. Equal.v1 is 0, v2 is out of bounds (use 0). Equal.v1 is 1, v2 is out of bounds (use 0). 1 > 0.
Return 1.. is a special character in many regex/split functions and needs to be escaped.The "convert to integer" approach automatically handles leading zeros and empty strings (if you use a default of 0). This makes the code much cleaner than manually stripping zeros.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Move Pieces to Obtain a String | Medium | Solve | |
| Magical String | Medium | Solve | |
| Reverse Words in a String II | Medium | Solve | |
| Reverse Words in a String | Medium | Solve | |
| String Compression | Medium | Solve |