This "Hard" problem asks you to count how many integers exist such that and the sum of the digits of is between min_sum and max_sum inclusive. and are given as strings because they can be very large (up to 100 digits).
Cisco and Goldman Sachs use this to test a candidate's mastery of Digit Dynamic Programming. Because the numbers are too large to be represented as standard integers, any simulation or iterative approach is impossible. This problem requires you to build numbers digit by digit while satisfying boundary constraints and sum constraints.
The pattern is Digit Dynamic Programming (Digit DP).
Result = Count(num2) - Count(num1 - 1).dp(index, current_sum, is_less, is_started):
index: Current digit position being filled.current_sum: Sum of digits selected so far.is_less: Boolean flag indicating if the number being built is already strictly less than the prefix of the bound..
current_sum = 1. At pos 1, can pick 0 (sum 1), 1 (sum 2). Numbers: 10, 11.current_sum = 2. At pos 1, can only pick 0 (sum 2). Number: 20.The most common mistake is failing to handle the "num1 - 1" string subtraction correctly, especially when is a power of 10 (like 1000). Another mistake is not including enough states in the DP (like the is_less constraint), leading to counts that exceed the bound .
Digit DP is a high-level technique. If you see a range problem where the numbers are given as strings, it is almost 100% a Digit DP problem. Practice the standard template until you can write the index and is_less transitions without hesitation.