The "Count Subarrays Where Max Element Appears at Least K Times interview question" is an optimization challenge. You are given an array and an integer k. You first find the maximum element in the entire array. Your task is to count the total number of subarrays that contain this maximum element at least k times.
Companies like Meta, Amazon, and Bloomberg use the "Count Subarrays Where Max Element coding problem" to test a candidate's ability to use the Sliding Window technique on more complex conditions. A brute-force approach would be , but the sliding window allows for an solution. It evaluations your ability to maintain a frequency count while expanding and shrinking a window.
This problem follows the Sliding Window and Two Pointers pattern.
left and right, and a counter countMax for occurrences of in the current window.right pointer. If arr[right] == M, increment countMax.countMax >= k:
left and ending at or after right is a valid subarray. There are n - right such subarrays. Add this to your total result.left pointer. If arr[left] == M, decrement countMax.Array: [1, 3, 2, 3, 3], . Max is 3.
right moves to index 3 (second '3'): countMax = 2.[1,3,2,3], [1,3,2,3,3]. (Count += 2).left to index 1. arr[0] was not 3, so countMax is still 2.[3,2,3], [3,2,3,3]. (Count += 2).
... and so on.Master the "Sliding Window interview pattern." It is the most common optimization for subarray problems. Practice identifying when a condition is "monotonic"—meaning if it's true for a window, it remains true as you expand it.
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