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Count the Number of Ideal Arrays

Hard
90.9%
Updated 6/1/2025

Count the Number of Ideal Arrays

What is this problem about?

The Count the Number of Ideal Arrays interview question defines an "ideal array" of length nn where each element is between 1 and mm inclusive, and every element is a multiple of its predecessor (i.e., arr[i] % arr[i-1] == 0).

You need to find the total number of such ideal arrays.

Why is this asked in interviews?

This "Hard" problem is a favorite at Microsoft and Amazon because it blends dynamic programming interview pattern with combinatorics and number theory. It tests the ability to recognize that since arr[i]arr[i1]imes2arr[i] \ge arr[i-1] imes 2 (unless they are equal), the number of distinct values in an ideal array is very small (log2(m)\le \log_2(m)). This observation is the key to an efficient solution.

Algorithmic pattern used

The problem is solved using DP and Stars and Bars.

  1. DP for Sequences: Let dp[len][val] be the number of strictly increasing sequences of length len ending with value val, where each element divides the next. Max len is 14\sim 14 because 214>1042^{14} > 10^4.
  2. Combinatorics: For a strictly increasing sequence of length LL, how many ways can we expand it to length nn by repeating elements? This is a "stars and bars" problem: choosing LL positions out of nn to change values, which is (n1L1)\binom{n-1}{L-1}.
  3. Combine: Total = L=114(v=1mdp[L][v])imes(n1L1)\sum_{L=1}^{14} (\sum_{v=1}^{m} dp[L][v]) imes \binom{n-1}{L-1}.

Example explanation

n=2,m=5n=2, m=5

  • Strictly increasing sequences:
    • Length 1: [1], [2], [3], [4], [5]. (5 total)
    • Length 2: [1,2], [1,3], [1,4], [1,5], [2,4]. (4 total)
  • Expanding to n=2n=2:
    • Length 1 sequences: (2111)=1\binom{2-1}{1-1} = 1 way. 5imes1=55 imes 1 = 5.
    • Length 2 sequences: (2121)=1\binom{2-1}{2-1} = 1 way. 4imes1=44 imes 1 = 4. Total = 9.

Common mistakes candidates make

  • Full DP: Attempting O(NimesM)O(N imes M) DP, which fails when n=109n=10^9.
  • Divisor calculation: Inefficiently finding divisors for the DP transition. Precomputing a sieve is better.
  • Combinations: Forgetting to handle large nn in the (n1L1)\binom{n-1}{L-1} calculation using modular inverse.

Interview preparation tip

Remember: If a sequence grows exponentially (like multiples), its length is bounded by log(Max)\log(Max). This "logarithmic bound" trick is common in number theory problems to reduce one dimension of a DP table.

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