Count the Number of Ideal Arrays
What is this problem about?
The Count the Number of Ideal Arrays interview question defines an "ideal array" of length n where each element is between 1 and m inclusive, and every element is a multiple of its predecessor (i.e., arr[i] % arr[i-1] == 0).
You need to find the total number of such ideal arrays.
Why is this asked in interviews?
This "Hard" problem is a favorite at Microsoft and Amazon because it blends dynamic programming interview pattern with combinatorics and number theory. It tests the ability to recognize that since arr[i]≥arr[i−1]imes2 (unless they are equal), the number of distinct values in an ideal array is very small (≤log2(m)). This observation is the key to an efficient solution.
Algorithmic pattern used
The problem is solved using DP and Stars and Bars.
- DP for Sequences: Let
dp[len][val] be the number of strictly increasing sequences of length len ending with value val, where each element divides the next. Max len is ∼14 because 214>104.
- Combinatorics: For a strictly increasing sequence of length L, how many ways can we expand it to length n by repeating elements? This is a "stars and bars" problem: choosing L positions out of n to change values, which is (L−1n−1).
- Combine: Total = ∑L=114(∑v=1mdp[L][v])imes(L−1n−1).
Example explanation
n=2,m=5
- Strictly increasing sequences:
- Length 1: [1], [2], [3], [4], [5]. (5 total)
- Length 2: [1,2], [1,3], [1,4], [1,5], [2,4]. (4 total)
- Expanding to n=2:
- Length 1 sequences: (1−12−1)=1 way. 5imes1=5.
- Length 2 sequences: (2−12−1)=1 way. 4imes1=4.
Total = 9.
Common mistakes candidates make
- Full DP: Attempting O(NimesM) DP, which fails when n=109.
- Divisor calculation: Inefficiently finding divisors for the DP transition. Precomputing a sieve is better.
- Combinations: Forgetting to handle large n in the (L−1n−1) calculation using modular inverse.
Interview preparation tip
Remember: If a sequence grows exponentially (like multiples), its length is bounded by log(Max). This "logarithmic bound" trick is common in number theory problems to reduce one dimension of a DP table.