The Count Univalue Subtrees interview question focuses on tree structures. A "univalue" subtree is a subtree where every node within it has the same value. Your task is to traverse a given binary tree and return the total count of such subtrees. It is important to remember that a single leaf node is always a univalue subtree.
Google and Bloomberg use this binary tree interview pattern to evaluate a candidate's proficiency with recursion and post-order traversal. It tests your ability to aggregate information from child nodes to make a decision about the parent node. It's an excellent problem for demonstrating clean recursive logic and handling null pointers.
This problem is best solved using Depth-First Search (DFS), specifically a Post-order Traversal.
Imagine a tree:
5
/
1 5
/ \
1 1 5
1 has children 1 and 1. Since all are the same value, it's univalue. Count = 4.5 (right side) has a child 5. It's univalue. Count = 5.5 has left child 1 and right child 5. Values don't match. Root is NOT univalue.
Total: 5.check(left) && check(right) might skip check(right) if check(left) is false. You must ensure both subtrees are processed to count their univalue subtrees.null child effectively "matches" any parent value for the univalue condition.When dealing with tree problems where a parent's state depends on its children, always think of post-order traversal. It ensures you have all the necessary information from the bottom before making a conclusion at the top.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Binary Tree Coloring Game | Medium | Solve | |
| Distribute Coins in Binary Tree | Medium | Solve | |
| Delete Leaves With a Given Value | Medium | Solve | |
| Sum Root to Leaf Numbers | Medium | Solve | |
| Flip Equivalent Binary Trees | Medium | Solve |