The Delete the Middle Node of a Linked List interview question asks you to identify and remove the central node of a singly linked list. If the list has nodes, the middle node is at index (0-indexed). This Delete the Middle Node of a Linked List coding problem is a variation of the classic "Find Middle" problem, but with the added requirement of modifying the structure.
Tech firms like Apple and Goldman Sachs use this to check for Two-Pointer interview patterns. It assesses whether you can find a specific position in a list without doing two full passes (one to count and one to delete). It's a test of efficient traversal and pointer manipulation.
This problem uses the Slow and Fast Pointers (Tortoise and Hare) pattern.
fast pointer that moves 2 steps at a time and a slow pointer that moves 1 step.fast reaches the end, slow will be at the middle. Keeping a prev pointer trailing slow allows you to re-link and delete.List: 1 -> 2 -> 3 -> 4 -> 5.
slow and fast start at 1. prev = null.fast moves to 3, slow to 2. prev = 1.fast moves to 5, slow to 3. prev = 2.fast.next is null, stop.3. Use prev (node 2) to skip 3: 2.next = 4.
Result: 1 -> 2 -> 4 -> 5.null).Whenever you need to find a relative position in a linked list (middle, from end, cycle start), immediately think of Slow and Fast Pointers. It's the standard optimization for list traversal.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Partition List | Medium | Solve | |
| Rotate List | Medium | Solve | |
| Swapping Nodes in a Linked List | Medium | Solve | |
| Remove Duplicates from Sorted List II | Medium | Solve | |
| Remove Nth Node From End of List | Medium | Solve |