In the Divide Array Into Arrays With Max Difference coding problem, you are given an array of integers and an integer . You need to divide the array into several groups, each of size exactly 3. Each group must satisfy one condition: the difference between the maximum and minimum elements in the group must be at most . If it's impossible to divide the entire array, return an empty list.
This "Medium" problem is popular at Salesforce and Amazon because it tests whether you can identify that Sorting is the prerequisite for a Greedy approach. It evaluations your understanding that to minimize the range of a group, the elements should be as close to each other as possible, which naturally happens in a sorted sequence.
This problem uses Greedy logic with Sorting.
arr[i], arr[i+1], arr[i+2].arr[i+2] - arr[i] <= k.nums = [1, 3, 4, 8, 7, 9], .
[1, 3, 4, 7, 8, 9].[1, 3, 4]. Max - Min = . .
Result: Empty list.
If :[1, 3, 4]. . (Valid).[7, 8, 9]. . (Valid).
Result: [[1, 3, 4], [7, 8, 9]].The "Max Difference" constraint in an array almost always implies sorting. Once the data is ordered, the "closest" elements are neighbors, which simplifies the decision-making process to a simple linear scan.
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