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Divide Array Into Equal Pairs

Easy
12.5%
Updated 8/1/2025

Divide Array Into Equal Pairs

What is this problem about?

The Divide Array Into Equal Pairs interview question asks you to determine if an integer array of length 2n2n can be partitioned into nn pairs such that each pair consists of two equal elements. Every element in the array must be part of exactly one pair. If the array can be completely divided into such pairs, the function should return True; otherwise, it should return False.

Why is this asked in interviews?

Companies like Microsoft and Amazon ask this coding problem to evaluate a candidate's basic data structure knowledge and their ability to perform frequency analysis. It's an "Easy" difficulty question that tests if you can identify the core requirement of a pairing problem: every unique element must appear an even number of times. It evaluates your choice between using a Hash Table, Sorting, or even Bit Manipulation.

Algorithmic pattern used

This problem follows a Frequency Counting pattern.

  1. Count: Iterate through the array and record the frequency of each integer using a Hash Map or a frequency array.
  2. Check: Iterate through the frequencies. If any frequency is odd, then that number cannot be perfectly paired.
  3. Result: If all frequencies are even, return True.

Example explanation

Array: [3, 2, 3, 2, 2, 2]

  1. Count 3s: There are two 3s. (Even).
  2. Count 2s: There are four 2s. (Even). Result: True. (Pairs: (3,3), (2,2), (2,2)).

Array: [1, 2, 3, 4]

  1. Count 1s: Only one 1. (Odd). Result: False.

Common mistakes candidates make

  • O(N^2) search: Using nested loops to find pairs and remove them, which is inefficient.
  • Ignoring Zeroes/Negatives: While usually not an issue with positive integers, a robust frequency map should handle any integer.
  • Forgetting to Check All: Returning True after seeing one pair, without verifying the entire array.

Interview preparation tip

Whenever you hear "pair up identical elements," your first instinct should be "frequency counts." Whether you use a Hash Map or sort the array first, the parity of the counts is the definitive signal.

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