The Equal Sum Arrays With Minimum Number of Operations coding problem gives you two arrays of integers, each containing values between 1 and 6 (simulating dice rolls). You want to make the sum of both arrays equal by changing the values of the elements. Each change counts as one operation. You need to find the minimum number of operations to achieve an equal sum, or return -1 if it's impossible.
This is a classic greedy interview pattern problem asked by companies like American Express. It tests a candidate's ability to identify the most impactful change at each step. It evaluates how you handle array sums and whether you can optimize the process by always picking the element that provides the largest possible reduction in the difference between the two sums.
The problem is solved using a Greedy strategy with Frequency Counting.
diff.diff, you can either:
6 - current_value).current_value - 1).diff <= 0.nums1 = [1, 2, 3, 4, 5, 6] (Sum 21), nums2 = [1, 1, 2, 2, 2, 2] (Sum 10).
diff = 11.
nums1 (decrease): [5, 4, 3, 2, 1, 0].nums2 (increase): [5, 5, 4, 4, 4, 4].
Combined Gains: [5, 5, 5, 4, 4, 4, 4, 4, 3, 2, 1].diff = 11 - 5 = 6.diff = 6 - 5 = 1.diff = 1 - 5 = -4. (Equal sum reached!).
Result: 3 operations.Whenever a problem asks for the "minimum number of operations" to reach a target value using a set of changes, always look for a greedy approach where you prioritize the most significant change first.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Minimum Number of Operations to Make Array Empty | Medium | Solve | |
| Minimum Operations to Make the Array Alternating | Medium | Solve | |
| Minimum Rounds to Complete All Tasks | Medium | Solve | |
| Minimum Total Cost to Make Arrays Unequal | Hard | Solve | |
| Largest Values From Labels | Medium | Solve |