The Find Anagram Mappings coding problem involves two arrays, A and B, where B is an anagram of A. This means B contains the same elements as A, but possibly in a different order. You need to return an index mapping array mapping where mapping[i] = j such that A[i] == B[j]. If there are multiple possible mappings (due to duplicate elements), any one will suffice.
This is a introductory question often used by Google to test knowledge of the Hash Table interview pattern. It evaluations whether you can use a lookup table to optimize what would otherwise be an search into a linear solution. It’s a basic test of data structure selection and attention to how duplicates are handled in a mapping context.
This problem uses a Hash Map to store the indices of elements in the second array.
B.{value: index}.
{value: [index1, index2, ...]}.A.A[i], look up its index in the Map and store it in the result array.A = [12, 28, 46], B = [46, 12, 28]
B: {46: 0, 12: 1, 28: 2}.A[0] (12): Result[0] = 1.A[1] (28): Result[1] = 2.A[2] (46): Result[2] = 0.
Result: [1, 2, 0].B for every element in A, leading to complexity.A = [10, 10] and B = [10, 10], failing to provide a valid mapping for both indices.When you need to find "where did this item move to?", always think of a Hash Map. Mapping values to their positions is a fundamental building block for many complex algorithms, including string transformations and sorting optimizations.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
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