In the Find Eventual Safe States interview question, you are given a directed graph where nodes are indexed from 0 to n-1. A node is considered "safe" if every possible path starting from that node eventually leads to a terminal node (a node with no outgoing edges). Your goal is to return a list of all safe nodes in ascending order. This Find Eventual Safe States coding problem is essentially about identifying nodes that cannot reach a cycle.
Companies like Uber, Microsoft, and Google use this problem to test a candidate's understanding of Cycle Detection and Topological Sort. It requires more than just a simple graph traversal; it requires identifying "toxic" components (cycles) and understanding how that toxicity propagates backward through the graph. It evaluations your proficiency with graph coloring or dependency resolution.
This utilizes the Graph, Depth-First Search, Topological Sort interview pattern. There are two popular ways to solve this:
Imagine a graph: 0 -> 1, 1 -> 2, 2 -> 0, 2 -> 3, 3 -> terminal.
Master the "Three-Color DFS" technique. It is the gold standard for cycle detection in directed graphs. Assigning states like WHITE, GRAY, and BLACK allows you to efficiently prune searches and identify cyclic dependencies in linear time.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Course Schedule IV | Medium | Solve | |
| Minimum Height Trees | Medium | Solve | |
| All Ancestors of a Node in a Directed Acyclic Graph | Medium | Solve | |
| Course Schedule | Medium | Solve | |
| Course Schedule II | Medium | Solve |