The Find the Array Concatenation Value interview question involves a unique reduction process. You pick the first and last elements of an array, concatenate their digits into a new number, and add that value to a running total. You repeat this for the new first and last elements until the array is empty. if only one element remains, you add its value directly. The goal is to return the final total sum.
IBM and other companies use the Find the Array Concatenation Value coding problem to test a candidate's ability to implement simulations accurately. It evaluates your skills in string manipulation (for concatenation) or mathematical digit shifting, as well as your mastery of the Two Pointers interview pattern.
This problem follows the Two Pointers and Simulation patterns.
left = 0 and right = n - 1.while loop that runs as long as left < right.nums[left] and nums[right]. This can be done by:val = nums[left] * 10^(digits in nums[right]) + nums[right].total, then increment left and decrement right.left == right, add the single remaining element to the total.Array: [7, 52, 2, 4]
total = 74.total = 74 + 522 = 596.
Result: 596.long.Be comfortable with two-pointer traversals. They are the standard way to process an array from "both ends inward." Also, practice finding the number of digits in an integer without strings ( or division).
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Apply Operations to an Array | Easy | Solve | |
| Partition Array According to Given Pivot | Medium | Solve | |
| Rearrange Array Elements by Sign | Medium | Solve | |
| Watering Plants II | Medium | Solve | |
| Adding Spaces to a String | Medium | Solve |