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Find the Count of Numbers Which Are Not Special

Medium
12.5%
Updated 8/1/2025

Asked by 1 Company

Find the Count of Numbers Which Are Not Special

What is this problem about?

The Find the Count of Numbers Which Are Not Special interview question is a number theory challenge. A "special number" is defined as a positive integer that has exactly three divisors. You are given a range [left, right], and your task is to count how many numbers in this range are not special. To solve this efficiently, you must first identify the unique mathematical property of numbers with exactly three divisors.

Why is this asked in interviews?

Google and other math-heavy tech companies use the Find the Count of Numbers Which Are Not Special coding problem to test a candidate's knowledge of prime numbers and squares. It evaluations if you can move beyond brute-force iteration (O(N)O(N)) and use mathematical properties to achieve a significantly faster solution (O(N)O(\sqrt{N})). It’s a classic Math interview pattern.

Algorithmic pattern used

This problem relies on Number Theory and the Sieve of Eratosthenes.

  1. Property: A number has exactly three divisors if and only if it is the square of a prime number. (e.g., 4=224 = 2^2, divisors: 1, 2, 4; 9=329 = 3^2, divisors: 1, 3, 9).
  2. Prime Sieve: Use a sieve to find all prime numbers up to right\sqrt{right}.
  3. Count Specials: For each prime pp found, calculate p2p^2. If p2p^2 falls within the range [left, right], it is a special number.
  4. Final Calculation: The result is (right - left + 1) - (count of special numbers).

Example explanation

Range: [4, 10].

  1. 103.16\sqrt{10} \approx 3.16. Primes up to 3 are {2, 3}.
  2. Calculate squares:
  • 22=42^2 = 4. (Inside range).
  • 32=93^2 = 9. (Inside range).
  1. Special numbers are {4, 9}. Count = 2.
  2. Total numbers in range: 104+1=710 - 4 + 1 = 7.
  3. Not special: 72=57 - 2 = 5. Result: 5.

Common mistakes candidates make

  • Brute Force Divisor Counting: Trying to count the divisors for every number in the range using a loop, which is O(NN)O(N \sqrt{N}) and will time out for large ranges.
  • Missing the Square Property: Failing to realize that only squares of primes have exactly three divisors. (e.g., 16=4216 = 4^2 has 5 divisors: 1, 2, 4, 8, 16).
  • Boundary Errors: Incorrectly calculating the number of elements in the range [left, right].

Interview preparation tip

Always look for the "divisor" properties of numbers. Remember that only perfect squares have an odd number of divisors. If the required number of divisors is small (like 3), there is usually a very specific prime-related property involved.

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