In the Find the Maximum Divisibility Score interview question, you are given two arrays: nums and divisors. The "divisibility score" of a divisor is the number of elements in nums that are divisible by it. You need to find the divisor with the maximum score. If multiple divisors have the same maximum score, you should return the smallest one among them.
DE Shaw uses this problem to test a candidate's ability to handle nested iterations and multiple tie-breaking conditions. It evaluations your proficiency with the Array interview pattern and your ability to track multiple metrics (score and value) simultaneously. It’s a basic test of clean coding and efficiency within constraints.
This is a Linear Scan problem with Tie-breaking logic.
maxScore = -1 and bestDivisor = Infinity.divisors array.nums array and count how many numbers are divisible by the current divisor (using num % divisor == 0).maxScore, update both maxScore and bestDivisor.maxScore, update bestDivisor = min(bestDivisor, currentDivisor).nums = [12, 6, 8], divisors = [2, 3]
bestDivisor = 2.maxScore to 0, which might not correctly handle cases where no numbers are divisible.When tracking the "best" element, always identify the primary criteria (score) and secondary criteria (value). Writing a clean if condition that handles both (count > maxScore || (count == maxScore && divisor < bestDivisor)) is a sign of a disciplined programmer.