This is the "Medium" version of the previous problem. In Find the Number of Good Pairs II, the arrays nums1 and nums2 can be much larger (), making an solution too slow. You still need to find pairs where nums1[i] is divisible by nums2[j] * k.
Companies like Amazon and Bloomberg use this to test your knowledge of Number Theory interview patterns and Frequency Maps. It evaluations whether you can optimize a divisibility check by looking at factors. Instead of checking every pair, you can count how many multiples of exist in the first array.
This problem uses Frequency Counting and Multiples Enumeration.
nums1.nums2:
target = y * k.target () up to the maximum value in nums1.nums1 to your total count.nums1 = [12, 6, 12], nums2 = [3], k = 1.
nums1: {12: 2, 6: 1}.target = 3 imes 1 = 3.nums2, which would cause you to re-calculate multiples for the same .When a problem involves "divisibility" across large arrays, think about "counting factors" or "iterating over multiples." This change in perspective (from pairs to factors) is a key optimization for many Array interview patterns.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| 4Sum II | Medium | Solve | |
| Brick Wall | Medium | Solve | |
| Find All Duplicates in an Array | Medium | Solve | |
| Maximum Linear Stock Score | Medium | Solve | |
| Finding the Users Active Minutes | Medium | Solve |