The Find the String with LCP interview question is a reverse-engineering challenge. You are given an matrix where lcp[i][j] is the length of the Longest Common Prefix (LCP) between the suffix of a string starting at index and the suffix starting at index . Your task is to reconstruct the lexicographically smallest lowercase English string that matches this matrix. If no such string exists, return an empty string.
Google uses the Find the String with LCP coding problem to test a candidate's ability to handle consistency checks and relational data structures. It requires you to use Union Find or greedy logic to determine which indices must have the same character and then validate if the resulting string actually produces the given LCP matrix.
This problem uses Greedy character assignment and Validation.
lcp[i][j] > 0, then s[i] must equal s[j]. Use a greedy pass to assign the smallest available characters ('a' to 'z') to indices, ensuring that connected indices get the same letter.dp[i][j] = (s[i] == s[j]) ? dp[i+1][j+1] + 1 : 0.Matrix : [[2, 0], [0, 1]].
lcp[0][1] = 0. So s[0] != s[1].s[0] = 'a'.s[1] = 'b'.lcp("ab") -> lcp(0,0)=2, lcp(0,1)=0, lcp(1,1)=1. Matches!
Result: "ab".lcp[i][j] > 0 but failing to check if the exact LCP values (like 2, 3, etc.) are consistent.Practice "Construction and Verification." This is a common Array interview pattern for hard problems. The key is to build the only possible candidate greedily and then spend time ensuring every single constraint in the input is satisfied.