The First Day Where You Have Been in All the Rooms interview question is a complex state-based simulation. There are rooms. Each day, if you visit room for an odd number of times, you must visit nextVisit[i] (where ) the next day. If you visit room for an even number of times, you move to room . You need to find the total number of days it takes to reach the last room.
ByteDance asks the First Day coding problem to test a candidate's mastery of Dynamic Programming. It is a difficult problem because the movements involve cycles (always going back to a previous room). It evaluation your ability to recognize that the "cost" to traverse a room is fixed and can be calculated using previous room costs.
This problem follows the Dynamic Programming with Cumulative Sums pattern.
dp[i] is the number of days needed to reach room from room 0.dp[i] days). On that day (odd visit), you are sent back to nextVisit[i]. To get back to again, you must spend the same amount of time it takes to go from nextVisit[i] to plus one day for the initial jump and one day for the final move.dp[i+1] = dp[i] + (dp[i] - dp[nextVisit[i]] + 1) + 1.dp[i+1] = 2 * dp[i] - dp[nextVisit[i]] + 2.nextVisit = [0, 0, 2].
dp[0] = 0.dp[1] = 2*dp[0] - dp[0] + 2 = 2.dp[2] = 2*dp[1] - dp[0] + 2 = 2*2 - 0 + 2 = 6.
Result: 6 days to reach the last room.(a - b) % mod can be negative. You must use (a - b + mod) % mod.Problems with "odd/even visit" rules often imply that you must pass through a state twice to move forward. This doubling effect is a major hint for Dynamic Programming interview patterns.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| House Robber II | Medium | Solve | |
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