The Flatten a Multilevel Doubly Linked List interview question involves a complex data structure where each node in a doubly linked list has a child pointer. This child pointer can point to another separate doubly linked list, which can also have children, creating a multi-level structure. Your goal is to "flatten" this into a single-level doubly linked list where the child nodes appear immediately after their parent.
Companies like Microsoft and Bloomberg use the Flatten a Multilevel Linked List coding problem to test a candidate's ability to manipulate pointers in a non-linear way. It evaluations your knowledge of Depth-First Search (DFS) and your ability to preserve the "doubly linked" property (both next and prev pointers) during a structural reorganization.
This problem is solved using the DFS (Recursion or Stack) pattern.
child:
next to the child.prev to the current node.next node.child pointer to null.List: 1 <-> 2 <-> 3. Node 2 has child A <-> B.
1 <-> 2 <-> A <-> B <-> 3.next node before re-linking the child list.next but forgetting to update the corresponding prev pointers, breaking the doubly-linked property.child pointer to null after flattening.Think of this as a "Depth-First" traversal. If you were to traverse this as a tree (where next and child are branches), the flattened order is exactly the same as a Pre-order DFS. Use this analogy to explain your logic clearly to the interviewer.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Convert Binary Search Tree to Sorted Doubly Linked List | Medium | Solve | |
| Linked List in Binary Tree | Medium | Solve | |
| Design Authentication Manager | Medium | Solve | |
| LRU Cache | Medium | Solve | |
| All O`one Data Structure | Hard | Solve |