In the Form Array by Concatenating Subarrays of Another Array coding problem, you are given a 2D array groups and a 1D array nums. You need to determine if you can choose non-overlapping subarrays from nums that perfectly match the arrays in groups, in the exact same order. For example, if groups = [[1, 2], [3, 4]], you need to find the sequence [1, 2] in nums, and then after that, find the sequence [3, 4].
Amazon asks this Array interview pattern problem to test your string/array matching skills and your ability to use Greedy algorithms. It evaluates whether you can manage multiple pointers and correctly reset your search state. It's a "Medium" problem that serves as a practical test of implementing a localized search within a larger search space.
This problem uses a Greedy and Two Pointers approach.
groups array. Let the current group be g.i for the nums array.g starting from nums[i].g starting at nums[k], move i to k + g.length and proceed to the next group.g in the remaining part of nums, return False.
Since we only move forward, picking the first available match for each group is the optimal greedy choice.groups = [[1, -1, -1], [3, -2, 0]], nums = [1, -1, 0, 1, -1, -1, 3, -2, 0]
[1, -1, -1].
[1, -1, 0]? No.[1, -1, -1]? Yes!i to .[3, -2, 0] starting from index 6.
[3, -2, 0]? Yes!
All groups found. Return True.nums starting index by 1, not by the partial match length.Practice writing a clean indexOf(array, subArray, startIndex) helper function. Separating the sub-array matching logic from the main group iteration makes your code much easier to read and debug.
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