The Game of Life coding problem asks you to simulate John Conway's cellular automaton. You are given an grid containing 0s (dead cells) and 1s (live cells). The grid evolves in discrete steps according to four rules:
Companies like Apple, Microsoft, and Google ask the Game of Life interview question to evaluate a candidate's ability to perform Matrix Simulation and manage state transitions without using extra memory. Since updates must happen simultaneously, modifying the board directly will affect subsequent calculations. This tests your cleverness in encoding intermediate states (e.g., using "2" to mean "was alive, now dead") to save space.
This problem uses an In-Place State Encoding pattern.
0: Was dead, remains dead.1: Was alive, remains alive.2: Was alive, now dead (treat as 1 when counting neighbors).3: Was dead, now alive (treat as 0 when counting neighbors).Suppose a cell is 1 and has 4 live neighbors (values are 1).
0 immediately, change it to 2.2 and knows "this cell was alive," counting it correctly.2 becomes 0.State encoding is a powerful trick for any grid-based cellular automaton problem. If you need to know both the old and new value simultaneously, map the transition to a new integer or use bit manipulation (e.g., store the next state in the 2nd bit of the integer).
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Diagonal Traverse | Medium | Solve | |
| Spiral Matrix II | Medium | Solve | |
| Spiral Matrix III | Medium | Solve | |
| Count Unguarded Cells in the Grid | Medium | Solve | |
| Spiral Matrix | Medium | Solve |