In the Generate Parentheses coding problem, you are given an integer . You need to generate all possible combinations of well-formed parentheses strings using pairs of brackets. For example, if , the valid strings are "(())" and "()()".
This is one of the most frequent technical interview questions, asked by Meta, Amazon, and Uber. it's a perfect test of Backtracking and recursive thinking. It evaluation whether you understand the rules of "well-formedness" (balance): you can never add more closing brackets than opening ones, and you can only use of each. It tests your ability to visualize a decision tree and handle state constraints.
This is a Backtracking problem.
openCount and closeCount.backtrack(currentString):
openCount < n, you can add a '('.closeCount < openCount, you can add a ')'.currentString.length == 2 * n, add the string to your result.
By following these rules, the recursion only explores valid paths, ensuring every generated string is well-formed.
"". open=0, close=0."(". open=1, close=0."((". open=2, close=0. (Now open is at limit)."()". open=1, close=1."((": can only add ')'. Result: "(())"."()": can only add '('. Result: "()(" "()()".closeCount exceed openCount or openCount exceed .Practice the Backtracking interview pattern. This problem is the "Hello World" of backtracking. Once you master it, you can solve similar problems like "Letter Combinations of a Phone Number" or "N-Queens."
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Palindrome Partitioning | Medium | Solve | |
| Partition String Into Minimum Beautiful Substrings | Medium | Solve | |
| Decode Ways | Medium | Solve | |
| Edit Distance | Medium | Solve | |
| Interleaving String | Medium | Solve |