Goat Latin
What is this problem about?
The Goat Latin interview question is a string manipulation task. You are given a sentence consisting of words separated by spaces. You need to convert the sentence to "Goat Latin" following three specific rules:
- If a word begins with a vowel ('a', 'e', 'i', 'o', or 'u'), append "ma" to the end of the word.
- If a word begins with a consonant, remove the first letter, append it to the end, and then add "ma".
- Add one letter 'a' to the end of each word based on its word index in the sentence, starting with 1 (e.g., the first word gets "a", the second gets "aa", etc.).
Why is this asked in interviews?
Companies like Apple and Meta use this String interview pattern as a warm-up or screening question. It tests a candidate's ability to follow a precise set of instructions and handle basic string operations (splitting, character checking, and concatenation). It evaluates if you can write clean, bug-free code for a problem with multiple edge cases (like uppercase vs. lowercase vowels).
Algorithmic pattern used
This problem uses a String Splitting and Simulation pattern.
- Split: Split the input sentence by spaces into an array of words.
- Iterate: Loop through the words while keeping track of the current index (1-based).
- Conditionals: For each word, check the first character (converted to lowercase for easy comparison).
- Transform: Apply the vowel or consonant rule.
- Append: Append the appropriate number of 'a's using the index.
- Join: Reconstruct the sentence by joining the transformed words with spaces.
Example explanation
Sentence: "I speak Goat Latin"
- Word 1 ("I"): Starts with vowel. Add "ma" -> "Ima". Add 1 'a' -> "Imaa".
- Word 2 ("speak"): Starts with consonant 's'. Move 's' to end -> "peaks". Add "ma" -> "peaksma". Add 2 'a's -> "peaksmaaa".
- Word 3 ("Goat"): Consonant 'G'. Move 'G' -> "oatG". Add "ma" -> "oatGma". Add 3 'a's -> "oatGmaaaa".
- Word 4 ("Latin"): Consonant 'L'. Move 'L' -> "atinL". Add "ma" -> "atinLma". Add 4 'a's -> "atinLmaaaaa".
Result:
"Imaa peaksmaaa oatGmaaaa atinLmaaaaa".
Common mistakes candidates make
- Case Sensitivity: Forgetting that vowels can be uppercase ('A', 'E', 'I', 'O', 'U').
- String Concatenation Overhead: Using
+= in a loop in languages where strings are immutable (like Java), leading to O(N2) memory usage. Using a StringBuilder or list join is better.
- Off-by-One: Starting the 'a' count at 0 instead of 1.
Interview preparation tip
Whenever you need to check if a character belongs to a specific set (like vowels), creating a predefined Set<Character> or a helper function isVowel(char) makes the code much cleaner and less error-prone than a long if statement.