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IPO

Hard
66%
Updated 6/1/2025

IPO

1. What is this problem about?

The IPO interview question is a resource maximization problem. You are given an initial capital ww and a set of projects. Each project ii has a profit pip_i and a minimum capital requirement cic_i. You can complete at most kk projects. Each time you finish a project, its profit is added to your total capital. Your goal is to find the maximum total capital you can achieve after finishing at most kk projects.

2. Why is this asked in interviews?

Companies like Amazon, Microsoft, and Salesforce ask the IPO coding problem to test a candidate's mastery of Greedy algorithms and Heaps. It evaluations whether you can identify that at any step, the best decision is to pick the most profitable project among those you can currently afford. It's a classic Priority Queue interview pattern.

3. Algorithmic pattern used

This problem follows the Two-Structure Greedy pattern.

  1. Sort: Sort all projects by their capital requirement cic_i in ascending order.
  2. Min-Max Strategy:
    • Use a pointer to track projects that you can afford with your current capital ww.
    • Push the profits of all affordable projects into a Max-Heap.
  3. Iteration: While you still have projects left to pick (k>0k > 0):
    • Pop the largest profit from the Max-Heap and add it to your capital ww.
    • Add any newly affordable projects to the Max-Heap.
    • If the Max-Heap is empty, you can't afford any more projects; stop.

4. Example explanation

k=2,w=0k = 2, w = 0. Projects: (profit: 1, capital: 0), (profit: 2, capital: 1), (profit: 3, capital: 1).

  1. Afford: Project (1, 0). Max-Heap: [1].
  2. Pick (1, 0): w=0+1=1,k=1w = 0 + 1 = 1, k = 1.
  3. Now afford: Projects (2, 1) and (3, 1). Max-Heap: [3, 2].
  4. Pick (3, 1): w=1+3=4,k=0w = 1 + 3 = 4, k = 0. Result: 4.

5. Common mistakes candidates make

  • Sorting by Profit: Only sorting by profit without considering if you can afford the project.
  • Re-sorting every time: Re-sorting the affordable list after every project (O(kNlogN)O(k \cdot N \log N)), which is too slow. A heap (O(NlogN)O(N \log N) total) is much faster.
  • Empty Heap: Not handling the case where you have kk remaining but cannot afford any available projects.

6. Interview preparation tip

Whenever you have "available options" that grow over time and you always need to pick the "best" one, think of a Priority Queue. This pattern is the go-to for optimization problems with dynamic constraints.

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