The Jump Game interview question asks if you can reach the last index of an array starting from the first. Each element in the array nums[i] represents your maximum jump length from that position. You don't have to jump the full distance; you can jump any distance from 0 up to nums[i].
This is a classic problem at Meta, Amazon, and Adobe. It tests your ability to simplify a problem using a Greedy approach. While it can be modeled as a search or DP problem, the greedy solution is and extremely elegant. It evaluates your ability to maintain a global state (the furthest reachable point) while scanning through an array.
This is a quintessential Greedy interview pattern problem.
maxReach initialized to 0.i is greater than maxReach, you can't even reach this index, so return false.maxReach = max(maxReach, i + nums[i]).maxReach ever becomes , return true.nums = [2, 3, 1, 1, 4]
maxReach = max(0, 0+2) = 2.maxReach = max(2, 1+3) = 4.maxReach = max(4, 2+1) = 4.maxReach is 4, which is the last index. Result: True.
nums = [3, 2, 1, 0, 4]maxReach becomes 3.maxReach = max(3, 3+0) = 3.i > maxReach.Whenever a problem asks "is it possible to reach X," first check if a Greedy strategy can track the "boundary of possibility." This often avoids the need for complex recursion or large DP tables. This is a core Array interview pattern.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Jump Game II | Medium | Solve | |
| Best Time to Buy and Sell Stock II | Medium | Solve | |
| Best Time to Buy and Sell Stock with Transaction Fee | Medium | Solve | |
| Minimum Sideway Jumps | Medium | Solve | |
| Video Stitching | Medium | Solve |