The Jump Game IX interview question introduces a set of rules based on relative magnitudes. You are at index 0 and want to reach the last index with minimum cost. From index i, you can jump to index j () if:
nums[i] <= nums[j] and for all in , nums[i] > nums[k]. (You jump to the first larger or equal element).nums[i] > nums[j] and for all in , nums[i] <= nums[k]. (You jump to the first smaller element).
Each jump to index has a cost costs[j].Companies like Medianet ask this to evaluate a candidate's proficiency with Monotonic Stacks and Dynamic Programming. It tests if you can identify "nearest" elements that satisfy a condition while skipping elements that don't. It evaluates your ability to build a sparse graph from array properties.
This problem follows the Monotonic Stack and DP pattern.
dp[i] is the minimum cost to reach index .dp[0] = 0.dp[j] = min(dp[j], dp[i] + costs[j]).nums = [3, 2, 4, 2], costs = [0, 5, 10, 2]
dp[1] = dp[0] + 5 = 5.dp[2] = dp[0] + 10 = 10.Practice using Monotonic Stacks to find "Nearest Greater/Smaller Element." It is the most frequent optimization for linear array problems. Combine this with DP to solve complex pathfinding tasks in Dynamic Programming interview patterns.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Minimum Total Space Wasted With K Resizing Operations | Medium | Solve | |
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| Check if There is a Valid Partition For The Array | Medium | Solve |