The Jump Game VII interview question is a reachability problem on a binary string. You start at index 0, which is always '0'. You can jump from index i to index j if:
s[j] == '0'i + minJump <= j <= min(i + maxJump, n - 1)
You need to determine if you can reach the last index of the string.Companies like Apple and Amazon use the Jump Game VII coding problem to see if a candidate can optimize a range-based reachability search. A standard BFS or DFS would be , which is too slow. It tests your ability to use Prefix Sums or a Sliding Window to track "how many reachable points exist in the current jump range."
This problem is solved using Dynamic Programming with a Sliding Window or Prefix Sum.
dp[i] is true if index i is reachable.dp[j] is true, you need to know if any index i in the range [j - maxJump, j - minJump] has dp[i] == true.reachable_count of indices within the current jump window that are marked as reachable.j:
dp[j - minJump] to the count (if valid).dp[j - maxJump - 1] from the count (if valid).s[j] == '0' and reachable_count > 0, then dp[j] = true.s = "011010", minJump = 2, maxJump = 3.
dp[0] = true.[2-3, 2-2] = [-1, 0]. dp[0] is in window. count=1. But s[2] is '1'. dp[2]=false.[0, 1]. dp[0] is in window. count=1. s[3] is '0'. dp[3]=true.[2, 3]. dp[3] is in window. count=1. s[5] is '0'. dp[5]=true.
Result: True.Range-based reachability can often be optimized by asking: "Is there at least one valid source in my range?" This turns a search problem into a Prefix Sum interview pattern or a sliding window count problem.