The "License Key Formatting interview question" involves cleaning and reformatting a string. You are given a string s (a license key with dashes) and an integer k. You need to reformat the string such that each group contains exactly k characters, except for the first group which can be shorter. All letters must be converted to uppercase, and groups must be separated by dashes. This "License Key Formatting coding problem" is a test of string manipulation and careful indexing.
Google has been known to ask this question frequently. It tests a candidate's proficiency with "String interview pattern" logic and their ability to handle formatting constraints. It evaluates whether you can efficiently build a new string while ignoring existing separators and applying new ones based on a specific count.
The most efficient approach is to process the string from right to left. By going backwards, you can easily ensure that every group has exactly k characters, and whatever is left over naturally falls into the first group at the end of your processing. You maintain a counter and insert a dash every time the counter reaches k, except for the very last characters. Finally, you reverse the result.
String: "5F3Z-2e-9-w", k = 4
+ in a loop in languages with immutable strings, which results in O(n^2) time. Using a StringBuilder or list is preferred.Whenever a problem specifies that the first group can be different but subsequent groups must be a fixed size, always try processing the data from the end. It usually makes the logic much simpler.
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|---|---|---|---|
| Count Asterisks | Easy | Solve | |
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| Generate a String With Characters That Have Odd Counts | Easy | Solve | |
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