This is the scaled-up Hard version of Part I. You are again asked to find the maximum area of an empty axis-aligned rectangle formed by points from the array. However, the number of points is massive (e.g., ). The or diagonal-scanning algorithms from Part I will result in an immediate Time Limit Exceeded. You must find an approach.
This is a highly advanced computational geometry problem. It is designed to test a candidate's mastery of the Sweep Line Algorithm and Segment Trees / Binary Indexed Trees. It is primarily seen in specialized algorithmic roles. It evaluates if you can process spatial data by moving an imaginary line across an axis, maintaining an active state of valid geometric bounds.
This problem strictly requires a Sweep Line paired with a Segment Tree / Balanced BST.
Due to the immense complexity of Sweep Line, a simplified abstraction:
Imagine moving a vertical scanner left to right.
At , we see points at and . We record in a dictionary: the edge (Y: 2 to 5) was seen at .
At , we see a point at . It doesn't complete a rectangle, but it "poisons" the space for future rectangles spanning across . We record its presence in a segment tree.
At , we see points at and .
We check our dictionary: (Y: 2 to 5) was last seen at . This forms a rectangle!
We query the segment tree: "Were there any points between and inserted between and ?"
The tree flags the point at . The rectangle is poisoned. We update the dictionary to state (Y: 2 to 5) is now seen at and keep sweeping.
Candidates almost universally attempt to optimize the solution using Hash Maps, failing to realize that worst-case inputs (like all points scattered randomly) still result in quadratic checks. Not recognizing that a massive in a geometry problem strictly dictates a Sweep Line algorithm is the primary failure point. Implementing the Segment Tree incorrectly, allowing points to "leak" through the query bounds, is the second most common error.
If you face Maximum Area Rectangle With Point Constraints II, you are in a top-tier interview. Focus heavily on articulating the Sweep Line strategy verbally before coding. Explain how sorting by X reduces the 2D problem to 1D states, and how a Segment Tree acts as a fast query mechanism for "boundary contamination." Even if you don't finish the Segment Tree code, accurately designing the Sweep Line architecture is a massive pass signal.