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Maximum Beauty of an Array After Applying Operation

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Updated 8/1/2025

Maximum Beauty of an Array After Applying Operation

What is this problem about?

The Maximum Beauty of an Array After Applying Operation interview question focuses on finding the maximum number of identical elements you can achieve in an array after modifying each element once. You are given an array of integers and a non-negative integer k. For each element in the array, you can choose any value within the range [element - k, element + k]. The "beauty" of the array is defined as the maximum frequency of any value in the array after these modifications.

Essentially, this is a range overlap problem. Each number x in the original array represents an interval [x - k, x + k]. The goal is to find a single point on the number line that is covered by the maximum number of these intervals.

Why is this asked in interviews?

This coding problem is a favorite among companies like Amazon and Google because it tests a candidate's ability to transform a seemingly complex modification problem into a classic interval or windowing problem. It evaluates:

  1. Mathematical Intuition: Can you see that modifying x by k is equivalent to saying x can represent any value in a specific range?
  2. Efficiency: A brute-force approach checking every possible value would be too slow. Candidates must use sorting or sliding window techniques to achieve an optimal time complexity.
  3. Optimization: The transition from individual element changes to finding the densest region of overlapping intervals is a key skill in algorithmic thinking.

Algorithmic pattern used

The most effective interview pattern for this problem involves Sorting combined with a Sliding Window or Two Pointers approach.

By sorting the array, we can represent the problem as finding the longest contiguous subarray where the difference between the maximum and minimum elements is at most 2k. Why 2k? Because if two numbers a and b (where a < b) can both be changed to the same value v, then a + k >= v and b - k <= v. This implies b - a <= 2k.

Example explanation

Imagine an array [4, 6, 1, 2] and k = 2.

  1. Sort the array: [1, 2, 4, 6].
  2. Range constraint: Any two numbers can become the same if their difference is at most 2 * k = 4.
  3. Sliding Window:
    • Start with [1]. Diff = 0 (<= 4). Length = 1.
    • Expand to [1, 2]. Diff = 1 (<= 4). Length = 2.
    • Expand to [1, 2, 4]. Diff = 3 (<= 4). Length = 3.
    • Expand to [1, 2, 4, 6]. Diff = 5 (> 4). Too wide!
    • Shrink from left: [2, 4, 6]. Diff = 4 (<= 4). Length = 3. The maximum beauty is 3.

Common mistakes candidates make

  • Checking every value: Trying to iterate through all possible values in the range [min(arr)-k, max(arr)+k] is highly inefficient if the range of numbers is large.
  • Incorrect Range: Using k instead of 2k as the threshold for the sliding window.
  • Not Sorting: Forgetting that a sliding window only works efficiently on sorted data for this specific problem.

Interview preparation tip

When you see a problem asking for the "maximum number of elements" that can satisfy a condition involving a "range" or "buffer" (k), always think about how those ranges overlap. Visualizing these as intervals on a 1D line often reveals that sorting and two-pointers will provide the most efficient solution.

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