Maximum Binary Tree II is a follow-up to the original Maximum Binary Tree problem. In this variation, you are given the root of an existing Maximum Binary Tree and a new integer val. You need to insert this val into the tree as if it were appended to the original array that created the tree.
The key constraint is that you don't have the original array; you only have the tree structure. You must maintain the "Maximum Binary Tree" properties: the root is the maximum, and the relative order of the original elements (plus the new one at the end) is preserved.
This problem, often seen in Meta interviews, tests your ability to:
The pattern used here is Recursive Tree Traversal. Since the new value is "appended" to the array, it logically exists to the right of all current elements. This means:
val is greater than the current root.val, the entire current tree must become the left child of the new val node (because all existing elements are to the left of the new one). The new node then becomes the new root.val is smaller than the current root.val, it must be inserted into the right subtree. We recurse on root.right.Original array was [2, 1, 5, 3]. Current Tree Root is 5.
New val to insert: 4.
4 with root 5. 4 < 5.5.right. The right child of 5 is 3.4 with 3. 4 > 3.4 is larger, the node 3 becomes the left child of the new node 4.4 becomes the new right child of 5.The "appended" logic is key: the new element is always "to the right" of everything currently in the tree.
Focus on the properties of the data structure. In a Maximum Binary Tree, the "right-most" path represents the elements at the end of the array. Understanding this "path-to-array" mapping is the secret to solving tree-modification problems efficiently.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Root Equals Sum of Children | Easy | Solve | |
| Count Nodes Equal to Sum of Descendants | Medium | Solve | |
| Binary Tree Pruning | Medium | Solve | |
| Inorder Successor in BST II | Medium | Solve | |
| Lowest Common Ancestor of a Binary Tree II | Medium | Solve |