Magicsheet logo

Maximum Difference Between Even and Odd Frequency I

Easy
12.5%
Updated 8/1/2025

Maximum Difference Between Even and Odd Frequency I

What is this problem about?

The "Maximum Difference Between Even and Odd Frequency I" is a string processing and frequency analysis problem. You are given a string, and you need to count how many times each character appears. Among the characters that appear an odd number of times, find the one with the maximum frequency. Among the characters that appear an even number of times, find the one with the minimum frequency. The goal is to return the difference between that maximum odd frequency and that minimum even frequency.

Why is this asked in interviews?

This Maximum Difference Between Even and Odd Frequency I interview question is popular because it tests multiple skills in a single task: hash table usage, frequency counting, and filtering based on parity. It assesses whether a candidate can efficiently collect statistics about a dataset and then apply specific criteria to those statistics. It’s a common pattern in data analysis and text processing tasks.

Algorithmic pattern used?

The algorithmic pattern used here is the Frequency Map (or Hash Table).

  1. Iterate through the string and count character frequencies using an array or map.
  2. Iterate through the recorded frequencies.
  3. If a frequency is odd, update your max_odd_freq.
  4. If a frequency is even, update your min_even_freq.
  5. Return the difference. This approach is very efficient, with O(n)O(n) time complexity to count the characters and O(1)O(1) space complexity (since there are a fixed number of possible characters, e.g., 26 lowercase letters).

Example explanation?

Suppose the string is "aaaaabbbbcc".

  • 'a' frequency = 5 (odd)
  • 'b' frequency = 4 (even)
  • 'c' frequency = 2 (even)
  1. Max odd frequency = 5 (from 'a').
  2. Min even frequency = 2 (from 'c').
  3. Difference = 5 - 2 = 3. The Maximum Difference Between Even and Odd Frequency I coding problem requires careful logic to ensure you only consider frequencies that actually exist in the string.

Common mistakes candidates make?

A common error is confusing the character itself with its frequency. Another mistake is not initializing the min_even_freq to a large enough value, leading to it staying at 0 (which is not a frequency found in the string). Candidates also sometimes fail to handle the case where there are no even frequencies or no odd frequencies, although the problem constraints usually guarantee at least one of each.

Interview preparation tip

Whenever a problem involves counting occurrences of elements, reach for the hash table interview pattern. Practice iterating over the keys and values of your map separately. Also, get comfortable with the modulo operator (% 2) to quickly determine if a number is even or odd.

Similar Questions