The Maximum Equal Frequency problem asks you to find the length of the longest prefix of an array such that after removing exactly one element from this prefix, all remaining elements have the same frequency. This is a subtle and tricky problem that requires careful bookkeeping of counts and frequencies.
Asked by companies like American Express, this problem tests a candidate's ability to handle complex frequency tracking. It's not just about how many times a number appears, but also about how many numbers have a certain frequency. It requires high attention to detail and the ability to identify all the different 'valid' states (e.g., all elements appear once, or one element appears once and others appear N times).
This problem uses the Hash Table and Frequency Count interview pattern. You need two maps:
count: Maps an element to its frequency.freq: Maps a frequency to the number of elements that have that frequency.
As you iterate through the array, you update these maps and check if the current prefix satisfies the condition.Array: [2, 2, 1, 1, 5, 3, 3]
Many candidates fail to identify all valid scenarios for 'equal frequency'. There are actually several:
When dealing with frequency of frequencies, use descriptive variable names like num_with_freq_x. This helps prevent confusion between the 'value', its 'count', and the 'frequency of that count'.
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