The "Merge In Between Linked Lists" coding problem asks you to take two given linked lists, list1 and list2, and modify list1 by removing a segment of its nodes and inserting list2 in their place. Specifically, you're given two integer indices, a and b, representing the start and end of the segment to be removed from list1. Your task is to connect the node before the a-th node in list1 to the head of list2, and connect the tail of list2 to the node after the b-th node in list1. The resulting linked list should start with list1's original head and contain list2 fully inserted. This Linked List interview question focuses on pointer manipulation and careful traversal.
This problem is a common sight in interviews for software engineering roles at companies like Meta, Amazon, and Google. It primarily assesses a candidate's ability to:
a-th, b-th, and their neighbors) requires precise traversal logic.a is 0 (merging at the beginning), b is the end of list1 (merging at the end), or list2 is empty.The primary algorithmic pattern used here is Two Pointers combined with Traversal. You typically need to iterate through list1 to locate specific nodes.
list1 from its head to find the node just before the a-th node (let's call it node_a_prev) and the node at the b-th position (let's call it node_b). This often involves a single pass or two separate passes.node_a_prev.next to point to the head of list2. Then, you need to find the tail of list2 and set its next pointer to node_b.next. This careful modification of next pointers is what allows for the "merge in between" operation.
No complex data structures are usually required beyond the linked list itself.Let list1 be 1 -> 2 -> 3 -> 4 -> 5 -> 6 and list2 be X -> Y -> Z.
Suppose a = 2 and b = 4 (0-indexed).
This means we want to remove nodes at indices 2, 3, and 4 from list1 (which are 3 -> 4 -> 5).
The node before the a-th node (index 2) is 2 (at index 1).
The node at the b-th node (index 4) is 5.
The node after the b-th node (index 4) is 6 (at index 5).
Our steps:
2 (the node at index a-1 = 1). Let's call it prev_a.5 (the node at index b). Let's call it node_b.prev_a.next to the head of list2 (X). So, 2 -> X.list2 (which is Z).Z.next to node_b.next (which is 6). So, Z -> 6.The resulting list will be 1 -> 2 -> X -> Y -> Z -> 6.
A very common mistake is off-by-one errors when traversing to find the a-th and b-th nodes. Forgetting that a and b might be 0-indexed or 1-indexed, or failing to differentiate between the node at an index and the node before an index, can lead to incorrect connections. Another frequent error is losing track of the head of list1 if a is 0 and the head needs to be updated. Not correctly finding the tail of list2 before linking it to the remaining part of list1 is also a common pitfall. Candidates sometimes also forget to handle cases where list2 might be empty, or list1 might be very short.
To ace the "Merge In Between Linked Lists" coding problem and similar Linked List interview patterns, practice drawing out linked list manipulations on paper. This helps visualize pointer changes. Work through problems that involve inserting, deleting, and reversing segments of a linked list. Focus on carefully traversing to the correct nodes using dummy nodes for easier head manipulation. Pay particular attention to off-by-one indices and null pointer checks. Implement a generic linked list node class and practice writing functions that take a head node and return a modified head. Always consider edge cases like an empty list, a single-node list, or operations at the very beginning or end of the list.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Delete Node in a Linked List | Medium | Solve | |
| Reverse Linked List II | Medium | Solve | |
| Insert into a Sorted Circular Linked List | Medium | Solve | |
| Split Linked List in Parts | Medium | Solve | |
| Odd Even Linked List | Medium | Solve |