The Minimum Cost to Cut a Stick problem gives you a stick of length n and a list of cuts you need to make. When you make a cut, the cost is equal to the length of the current piece of stick you are cutting. You can make the cuts in any order. The goal is to find the minimum total cost to complete all the cuts.
This is a classic Minimum Cost to Cut a Stick interview question at Google, Meta, and Microsoft. It is a variation of the "Matrix Chain Multiplication" or "Optimal Binary Search Tree" problem. It tests Dynamic Programming on intervals. It evaluates if a candidate can define a subproblem as "cutting a stick segment between two existing cut points."
The Interval Dynamic Programming interview pattern is the standard solution.
0 and n to the cuts array and sort it.dp[i][j] be the minimum cost to make all cuts between cuts[i] and cuts[j].k (where i < k < j) is:
(cuts[j] - cuts[i]) + dp[i][k] + dp[k][j].k to find the minimum.Stick 7, cuts [1, 3, 4, 5].
[0, 1, 3, 4, 5, 7].0 and 7 at 3: Cost is 7 (length) + dp(0, 3) + dp(3, 7).cuts array mixed up with the actual coordinates on the stick.Master Interval DP. If you can solve this and "Burst Balloons," you have a solid grasp of how to split a large problem into two smaller independent segments based on a choice made in the middle.
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