This problem is a variation of the classic "Valid Parentheses" challenge but with a unique twist: one opening parenthesis ( must be matched by exactly two consecutive closing parentheses )).
Given a string containing only ( and ), you need to find the minimum number of insertions (either ( or )) required to make the string "balanced" according to this rule. A string is balanced if every ( has a matching )) and they are correctly nested.
Meta and Amazon use this problem to evaluate a candidate's ability to handle Stack-based logic and State tracking. It’s more complex than the standard balancing problem because of the "double-close" requirement, which introduces more edge cases.
Interviewer's look for:
) at the end, or a ) followed by a ()?The problem is best solved using a Greedy approach with a counter (simulating a stack).
insertions (total characters added) and needed_right (the number of ) we are currently looking for).(:
), it means we had a single ) that wasn't followed by another. We must insert one ) to complete it and decrement needed_right.needed_right (because this new ( needs a pair).):
needed_right.needed_right becomes negative, it means we have an extra ). We must insert a ( and set needed_right to 1 (because the new ( needs 2, and we just used 1).String: (()))
(: needed_right becomes 2.(: needed_right becomes 4.): needed_right becomes 3.): needed_right becomes 2.): needed_right becomes 1.
Wait, let's look at it differently.
At the end, if needed_right is 1, it means we have a trailing single ).
Actually, the simplest logic:( adds 2 to "required closing".) uses 1 from "required closing".| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Check if a Parentheses String Can Be Valid | Medium | Solve | |
| Maximum Score From Removing Substrings | Medium | Solve | |
| Minimum Add to Make Parentheses Valid | Medium | Solve | |
| Construct Smallest Number From DI String | Medium | Solve | |
| Minimum Additions to Make Valid String | Medium | Solve |