This problem describes a process where you can reduce the length of a string by removing characters. The rule is: if you have a character at index i, and you can find the same character at some index j < i (to its left) and some index k > i (to its right), you can remove both the character at j and the character at k.
You want to apply this operation as many times as possible to minimize the final length of the string.
This question, recently asked by IBM and Amazon, tests Pattern Recognition and Hash Table usage. It looks like a complex simulation, but there's a simple mathematical rule hidden beneath the surface. Interviewer's look for:
The pattern is Frequency Counting and Parity Logic.
c times:
c is odd, we can keep reducing until only 1 character remains. (e.g., 3 -> 1, 5 -> 3 -> 1).c is even (and c > 0), we can keep reducing until only 2 characters remain. (e.g., 4 -> 2, 6 -> 4 -> 2).String: abaacbc
a: 3 times. 3 is odd reduced to 1.b: 2 times. 2 is even remains 2.c: 2 times. 2 is even remains 2.
Total minimum length: .Wait, why 1 or 2?
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Sum of Beauty of All Substrings | Medium | Solve | |
| Minimum Number of Steps to Make Two Strings Anagram | Medium | Solve | |
| Bulls and Cows | Medium | Solve | |
| Make Number of Distinct Characters Equal | Medium | Solve | |
| Minimum Length of Anagram Concatenation | Medium | Solve |