The Minimum Right Shifts to Sort the Array problem gives you a circular array and asks for the minimum number of right-rotation shifts needed to sort it in non-decreasing order. A right shift moves the last element to the front. If no number of shifts can sort the array, return -1. This Minimum Right Shifts to Sort the Array interview question is an easy but tricky problem about rotation and sortedness.
Amazon and Accenture ask this to test basic array reasoning and edge case awareness. It's deceptively simple — the easy difficulty rating can catch candidates who overthink it. The core question is: is the array already a rotation of a sorted array? And if so, how many shifts are needed? The array interview pattern applies directly.
The approach is linear scan for the rotation point. In a valid right-shifted sorted array, there is exactly one "drop point" — where arr[i] > arr[i+1]. Find this drop. The number of right shifts needed equals n - dropIndex. Additionally, the last element must be ≤ the first element (to close the circular sort). If there are multiple drop points, return -1.
Array: [3, 4, 5, 1, 2].
Array: [2, 1, 4, 3] → two drop points → return -1.
n - dropIndex.Easy problems are often about correctly handling edge cases. For this problem, list all cases before coding: already sorted (0 shifts), one drop point with valid wrap (n - drop shifts), multiple drops (-1), and a single-element array (0 shifts). Drawing the rotation on paper helps. Don't let "easy" difficulty make you skip edge case analysis — interviewers specifically watch for this.