The Most Frequent Even Element problem gives you an integer array and asks you to return the most frequently occurring even number. If there's a tie, return the smallest such number. Return -1 if no even number exists. This Most Frequent Even Element coding problem is a clean frequency counting exercise with a simple tiebreaking rule.
Amazon, Google, and Bloomberg include this as a quick screening problem to test basic hash map usage and tiebreaking logic. It validates that candidates can implement frequency counting correctly and handle edge cases (no even elements, multiple elements tied for most frequent). The array, hash table, and counting interview pattern is directly applied.
Hash map frequency count + linear scan. Iterate the array, counting frequencies of even numbers only (skip odd numbers). After building the frequency map, find the entry with the maximum frequency. On ties, return the smaller key.
Array: [0, 1, 2, 2, 4, 4, 1]. Even numbers: [0, 2, 2, 4, 4]. Frequencies: {0:1, 2:2, 4:2}.
Array: [1, 3, 5]: no even numbers → return -1.
Frequency counting problems with tiebreaking rules are common easy-level interview questions. The pattern: build frequency map over filtered elements, find the maximum frequency, then find the minimum key with that frequency (or use min(key for key, freq in map.items() if freq == maxFreq)). This one-liner approach demonstrates clean Pythonic thinking. Practice similar problems with different tiebreaking conditions (e.g., largest, first occurrence, most recent) to handle all variants quickly.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Number of Equivalent Domino Pairs | Easy | Solve | |
| Find Lucky Integer in an Array | Easy | Solve | |
| Sum of Unique Elements | Easy | Solve | |
| Count Elements With Maximum Frequency | Easy | Solve | |
| Most Frequent Number Following Key In an Array | Easy | Solve |