Pascal's Triangle is one of the most fundamental problems in combinatorics and dynamic programming. Given numRows, generate the first numRows rows of Pascal's triangle, where each element is the sum of the two elements directly above it. This easy coding problem tests 2D array construction with the recurrence relation. The array and dynamic programming interview pattern is demonstrated.
J.P. Morgan, Cisco, Uber, Goldman Sachs, Oracle, Google, and many others ask this as a warm-up problem. It tests basic 2D array construction, recurrence relations, and base case handling. It's also a gateway to combinatorial math (binomial coefficients).
Row-by-row DP construction. Each row starts and ends with 1. For row i and position j (1 ≤ j ≤ i-1): triangle[i][j] = triangle[i-1][j-1] + triangle[i-1][j]. Build row by row.
numRows=5. Build rows:
Pascal's Triangle builds the foundation for understanding binomial coefficients: C(n,k) = triangle[n][k]. Practice generating it iteratively (build row by row) and recognize its applications: combinatorics, probability, and polynomial expansion. After this, solve Pascal's Triangle II (kth row only with O(k) space) to reinforce space optimization skills.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Pascal's Triangle | Easy | Solve | |
| Pascal's Triangle II | Easy | Solve | |
| Min Cost Climbing Stairs | Easy | Solve | |
| Pascal's Triangle II | Easy | Solve | |
| Best Time to Buy and Sell Stock | Easy | Solve |