The Print Binary Tree problem asks you to represent a binary tree in a matrix of height h and width 2^h - 1, where the root is centered and child nodes are placed at specific positions. This coding problem calculates precise grid positions using tree height and recursive placement. The BFS, DFS, binary tree, and tree interview pattern is demonstrated through position calculation.
Meta, Amazon, and Google ask this to test understanding of binary tree structure — specifically the mathematical relationship between a node's level and its column position. The recursive position calculation is elegant and tests tree layout intuition.
Recursive DFS with position calculation. Compute tree height h. Create (h+1) × (2^(h+1) - 1) matrix filled with "". Place root at (0, mid) where mid = (width-1)/2. For each node at (row, col): left child at (row+1, col - 2^(h-row-1)), right child at (row+1, col + 2^(h-row-1)). Recurse.
Tree: 1→(2,3). Height=2. Width = 2^3-1=7. Root at (0,3).
["","","","1","","",""]
["","2","","","","3",""]
Print Binary Tree requires deriving the position formula mathematically. At level d, the left subtree width is 2^(h-d) - 1 and root is at the midpoint. Practice deriving similar tree layout formulas by working out small examples (height 1, 2, 3). Understanding the relationship between tree structure and grid coordinates is useful for visualization, debugging, and algorithm explanations in interviews.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Maximum Level Sum of a Binary Tree | Medium | Solve | |
| Count Good Nodes in Binary Tree | Medium | Solve | |
| Deepest Leaves Sum | Medium | Solve | |
| Find Largest Value in Each Tree Row | Medium | Solve | |
| Add One Row to Tree | Medium | Solve |