The Rotate Array interview question asks you to rotate an integer array to the right by k steps in-place, using O(1) extra space. Rotating right by k means the last k elements move to the front, and the remaining elements shift right. For example, rotating [1,2,3,4,5] by 2 gives [4,5,1,2,3].
This problem is asked at Apple, Samsung, Uber, Goldman Sachs, Microsoft, Meta, Amazon, Google, Bloomberg, and Adobe because it has multiple solutions of increasing elegance — brute force, extra array, cyclic replacement, and the elegant triple-reversal technique. It tests in-place manipulation, modular arithmetic for handling k > n, and understanding the relationship between rotation and reversal.
The most elegant pattern is the triple reversal: (1) reverse the entire array, (2) reverse the first k elements, (3) reverse the remaining n-k elements. Always reduce k to k % n first to handle cases where k ≥ n.
The cyclic replacement pattern is also O(1) space: start at each position, follow the "destination" chain (i + k) % n, placing elements until the cycle completes.
Array: [1, 2, 3, 4, 5, 6, 7], k = 3.
k = 3 % 7 = 3.
Step 1 — Reverse all: [7, 6, 5, 4, 3, 2, 1].
Step 2 — Reverse first 3: [5, 6, 7, 4, 3, 2, 1].
Step 3 — Reverse last 4: [5, 6, 7, 1, 2, 3, 4].
Result: [5, 6, 7, 1, 2, 3, 4]. Correct!
Extra array approach (O(n) space): new_arr[(i+k) % n] = nums[i] for each i. Then copy back.
k modulo n first — if k = n, no rotation is needed.[0, k-1] and [k, n-1] after the full reversal.For the Rotate Array coding problem, the array and two-pointer interview pattern via triple reversal is the most interview-friendly approach. Memorize the three reversal steps and the k %= n preprocessing. Interviewers at Netflix and Capital One sometimes ask for all three approaches (brute force, extra array, triple reversal) and ask which is best — triple reversal wins on both time and space complexity. Practice explaining the mathematical intuition: reversing the whole array and then fixing the two halves restores the correct order.
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