The "Sort Array by Increasing Frequency" problem asks you to rearrange an array based on two criteria:
This is a great exercise in multi-level sorting. You must first count how many times each number appears and then use those counts to reorder the original array.
Companies from Goldman Sachs to Adobe use this interview question to test a candidate's ability to use Hash Tables (for counting) and custom sorting logic. It’s a practical problem that mimics real-world data processing tasks where you often need to sort by one attribute and then "break ties" using another. It evaluates whether you can write clean, concise code for multi-step data transformations.
The pattern involves a two-step approach:
Input: [1, 1, 2, 2, 2, 3]
A common mistake is forgetting the second sorting criteria (descending order for tie-breaks). Another error is inefficiently re-counting frequencies inside the sort function, which leads to or worse performance. You should always pre-calculate the frequencies in time. Some candidates also struggle with the syntax for complex sorting, especially in languages like Java or C++ where multi-level comparators can be verbose.
To master the "Sort Array by Increasing Frequency interview question," practice using frequency maps and custom sorting keys. In Python, you can use sort(key=lambda x: (freq[x], -x)). In other languages, learn how to use thenComparing or multiple if statements in a comparator. Understanding how to combine data structures like maps and lists effectively is a key skill for any software engineer.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Rank Transform of an Array | Easy | Solve | |
| Contains Duplicate | Easy | Solve | |
| Make Two Arrays Equal by Reversing Subarrays | Easy | Solve | |
| Smallest Missing Integer Greater Than Sequential Prefix Sum | Easy | Solve | |
| Check if Array is Good | Easy | Solve |