The Special Binary String interview question involves a set of binary strings defined by two rules: the number of 0's and 1's are equal, and every prefix has at least as many 1's as 0's. These are essentially "balanced" strings, similar to valid parentheses. The goal is to perform any number of swaps between two adjacent, non-empty special substrings to make the overall string lexicographically as large as possible.
This is a HARD level Special Binary String coding problem often asked by top-tier companies like Microsoft and Google. It tests a candidate's ability to recognize recursive structures and map a problem from one domain (binary strings) to another (trees or nested parentheses). It requires a deep understanding of Recursion and string manipulation, as well as the ability to identify the optimal "greedy" strategy for sorting.
The core pattern is Recursion. A special binary string can be viewed as a set of nested special strings. By stripping the outer '1' and '0', you are left with another special string (or a sequence of them). You recursively process these inner parts to make them lexicographically largest, then sort the resulting substrings in descending order before re-assembling them. This ensures that the largest components come first, satisfying the "largest lexicographical" requirement.
Take the string 11011000.
1(101100)0.10 and 1100.1100 is larger than 10.Whenever you see "equal number of 0s and 1s" and "prefix condition," immediately think of valid parentheses. Replace '1' with '(' and '0' with ')'. This often makes the structural properties of the problem much more intuitive and easier to solve using tree-based recursion.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Parsing A Boolean Expression | Hard | Solve | |
| Integer to English Words | Hard | Solve | |
| Regular Expression Matching | Hard | Solve | |
| Find Kth Bit in Nth Binary String | Medium | Solve | |
| Strobogrammatic Number II | Medium | Solve |