The Spiral Matrix IV interview question combines matrix simulation with linked list traversal. You are given the dimensions m x n of a matrix and the head of a linked list. You need to fill the matrix with the values from the linked list in a spiral order. If the linked list ends before the matrix is full, the remaining cells should be filled with -1. This is a multi-data-structure problem that tests your ability to synchronize different traversal methods.
This Spiral Matrix IV coding problem is often used by Microsoft and Google to see if a candidate can handle two different pointers: one for the matrix boundaries and one for the linked list nodes. It requires careful coordination—as you move through the matrix in a spiral, you must also advance through the linked list, checking for the null terminator at each step.
This problem uses the Linked List traversal pattern merged with Matrix Simulation. You initialize an m x n matrix filled with -1s. Then, you apply the standard four-boundary spiral logic. For each cell you visit in the spiral, you take the current node's value, place it in the matrix, and move to the next node. If the next node is null, you stop filling and let the remaining -1s stay as they are.
Grid: 3x3, Linked List: 3 -> 0 -> 2 -> 6 -> 8.
[[3, 0, 2],
[-1, -1, 6],
[-1, -1, 8]]
(Note: the spiral continues into (2,1), (2,0), etc., but the list is empty).
null before trying to access its value.When dealing with multiple data structures, think about which one "drives" the loop. In this case, the matrix spiral order drives the movement, while the linked list provides the values. Always ensure your "consumer" (the matrix filler) gracefully handles the case where the "provider" (the linked list) runs dry.
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|---|---|---|---|
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