In this problem, you are given an integer n in base 10 and a base k. Your task is to convert n into its representation in base k and then find the sum of the digits of that new representation. For example, if n = 34 and k = 6, 34 in base 6 is 54 (because 5*6 + 4 = 34). The sum of the digits 5 and 4 is 9.
This "Easy" level problem is frequently asked at companies like Amazon to test basic mathematical logic and comfort with number bases. It assesses whether a candidate knows how to perform base conversions using the standard "divide and modulo" approach. It's a foundational skill for understanding how data is represented in different formats (binary, octal, hexadecimal) within a computer.
The algorithmic pattern is "Base Conversion using Iterative Division." To convert a number n to base k, you repeatedly take the remainder of n divided by k (n % k) to get the current digit, and then update n by dividing it by k (n // k). You keep track of the sum of these remainders until n becomes 0.
Let's convert n = 42 to base k = 4.
n = 42 // 4 = 10.n = 10 // 4 = 2.n = 2 // 4 = 0.
Digits in base 4 are {2, 2, 2}.
Sum of digits: 2 + 2 + 2 = 6.n > k instead of n > 0, which might miss the final leading digit.n % 10) applies to any base k.Be prepared to handle base conversion in any coding interview. It is a very common sub-task in more complex problems. Remember that n % k gives you the digit and n / k moves you to the next position. Practice doing this manually for binary (base 2) and hexadecimal (base 16) to build intuition.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Armstrong Number | Easy | Solve | |
| Number of Days in a Month | Easy | Solve | |
| Prime Arrangements | Easy | Solve | |
| Construct the Rectangle | Easy | Solve | |
| Alternating Digit Sum | Easy | Solve |