In the Take K of Each Character From Left and Right interview question, you are given a string s consisting of characters 'a', 'b', and 'c', and an integer k. You can take characters from either the left or the right end of the string. Your goal is to find the minimum number of minutes (one minute per character) required to take at least k of each character. If it's impossible, return -1.
This "Medium" difficulty problem is popular at Meta and Amazon because it tests your ability to transform a "taking from ends" problem into a sliding window problem. It evaluates your skills in string analysis and optimization. Instead of simulating the removal from both ends, a more efficient approach is to find the longest "middle" part of the string that can be left behind while still satisfying the k requirement for each character.
The primary pattern is the Sliding Window interview pattern.
k, return -1.k of 'a', 'b', and 'c'.count - k or less.total_length - max_window_length.String: aabaaaacaabc, k = 2.
8 - 2 = 6.2 - 2 = 0.2 - 2 = 0.
We look for the longest window that has no 'b's and no 'c's and at most 6 'a's. In our string, aaaa is a valid window. If we leave that, we took everything else.A common error is trying to use a greedy approach (taking characters from whichever side seems "better" at the moment), which doesn't always lead to the global minimum. Another mistake is forgetting to handle the case where the entire string is not enough to satisfy the k requirement. Some candidates also struggle with the window conditions—specifically, how to define the "limit" for each character inside the window.
To excel in the Take K of Each Character From Left and Right coding problem, practice converting "two-ended" removal problems into "middle" window problems. This is a very common trick in competitive programming. Mastery of the Sliding Window interview pattern is essential for reducing O(n²) or O(2^n) search problems to linear O(n) solutions.