Imagine a queue of people waiting to buy tickets. Each person i wants to buy a specific number of tickets tickets[i]. It takes 1 second to buy a single ticket. After buying a ticket, if a person still needs more, they move to the back of the queue. Given the ticket requirements of everyone in the queue and the position k of a specific person, how many seconds will it take for that person to finish buying all their tickets?
This time needed to buy tickets interview question is an "easy" level problem used by companies like Uber, Microsoft, and Meta. It tests your ability to simulate a queue-based process and potentially identify a mathematical shortcut to avoid a full simulation. It evaluates your understanding of basic data structures (queues) and your ability to optimize simple loops.
This problem follows the Array, Queue, Simulation interview pattern.
k reaches 0 tickets.i before or at position k, they will buy at most tickets[k] tickets (or fewer if they need less).i after position k, they will buy at most tickets[k] - 1 tickets because person k finishes their last ticket before those people get their next turn.i.Tickets: [2, 3, 2], k = 2 (The person who wants 2 tickets at the end).
In "Time Needed to Buy Tickets coding problem," a common mistake is an "off-by-one" error in the mathematical shortcut, such as counting too many tickets for people behind position k. Another error is using a full simulation when the input sizes are large, which could lead to slow performance compared to the O(n) sum approach.
When you see a simulation problem where you only care about one specific element, try to calculate its contribution and the contribution of its neighbors directly. This "contribution-based" thinking is a key step toward optimizing many simulation and array problems.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Time Taken to Cross the Door | Hard | Solve | |
| Number of Students Unable to Eat Lunch | Easy | Solve | |
| Reveal Cards In Increasing Order | Medium | Solve | |
| Build Array from Permutation | Easy | Solve | |
| Concatenation of Array | Easy | Solve |