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Total Characters in String After Transformations II

Hard
12.5%
Updated 8/1/2025

Total Characters in String After Transformations II

What is this problem about?

The "Total Characters in String After Transformations II coding problem" is an advanced version of the transformation challenge. In this iteration, the transformation rules might be more complex, or the number of transformations could be significantly larger (e.g., up to 10910^9). You are given a string and a set of rules where each character maps to a sequence of characters. The task is to find the total length of the string after all transformations are complete, usually modulo a large prime number like 109+710^9 + 7.

Why is this asked in interviews?

This "Total Characters in String After Transformations II interview question" is a favorite for senior engineering roles because it tests the transition from simple iterative counting to matrix exponentiation. It assesses your ability to recognize linear recurrence relations and apply advanced mathematical optimizations. Companies like Meta and Google use these problems to identify candidates who can optimize algorithms to handle extreme scales that would be impossible with standard iterative methods.

Algorithmic pattern used

The "Math, Hash Table, Counting, String, Dynamic Programming interview pattern" is extended here with "Matrix Exponentiation." Since each character's count in step t+1 is a linear combination of character counts in step t, we can represent the transformation as a 26×2626 \times 26 matrix. Multiplying the initial character frequency vector by this matrix raised to the power of the number of transformations gives the final frequency vector. This reduces the time complexity from O(T×26)O(T \times 26) to O(263logT)O(26^3 \log T), where TT is the number of transformations.

Example explanation

Imagine a world with only 'a' and 'b'. Rules: 'a' -> "aa", 'b' -> "ab". Transformation Matrix M:

  • From 'a': 2 'a's, 0 'b's -> Column 0: [2, 0]
  • From 'b': 1 'a', 1 'b' -> Column 1: [1, 1] Matrix M = [[2, 1], [0, 1]]. If we start with "a" (Vector V = [1, 0]) and want 10 transformations, we calculate M10×VM^{10} \times V. The result vector's components summed up will give the total characters. This approach is lightning fast even for billions of transformations.

Common mistakes candidates make

The most common error in the "Total Characters in String After Transformations II coding problem" is not recognizing that matrix exponentiation is required for very large transformation counts. Candidates often try to use a simple loop, which is doomed to fail. Another mistake is incorrect matrix construction—swapping rows and columns or failing to correctly account for all characters in the transformation rules. Forgetting to apply the modulo at each multiplication step is also a frequent oversight.

Interview preparation tip

To excel in the "Math, Hash Table, Counting, String, Dynamic Programming interview pattern," specifically for HARD problems, study the basics of linear algebra and matrix multiplication. Practice implementing a generic multiply and power function for matrices. Understanding how to convert a set of linear rules into a matrix is a highly valuable skill that applies to many "counting" problems in competitive programming and high-level interviews.

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